Ask Question
13 August, 13:55

A mass is hung from a spring and set in motion so that it oscillates continually up and down. The velocity v of the weight at time t is given by the equation v=-2 cos (3πt) with v measured in feet per second and t measured in seconds. Determine the maximum velocity of the mass and the amount of time it takes for the mass to move from its lowest position to its highest position.

+3
Answers (1)
  1. 13 August, 14:50
    0
    the maximum velocity of the mass v (max) = 2 ft/s

    the amount of time it takes for the mass to move from its lowest position to its highest position∆t = 1/3 seconds = 0.33 seconds

    Explanation:

    Given the velocity equation;

    v=-2 cos (3πt)

    The maximum velocity would be at cos (3πt) = 1 or cos (3πt) = - 1

    v (max) = - 2 * - 1 = 2 ft/s

    The time taken for the mass to move from lowest position to highest position

    At Lowest position, vertical velocity equals zero.

    At highest position, vertical velocity equals zero.

    The time taken for the mass to move from one v = 0 to the next v = 0

    Cos (π/2) = 0 and

    Cos (3π/2) = 0

    For the first;

    Cos (3πt) = cos (π/2)

    3πt1 = π/2

    t1 = π/2 (3π)

    t1 = 1/6 second

    For the second;

    Cos (3πt) = cos (3π/2)

    3πt2 = 3π/2

    t2 = 3π/2 (3π)

    t2 = 1/2 second

    ∆t = t2 - t1 = 1/2 - 1/6 = 3/6 - 1/6 = 2/6 = 1/3 seconds

    ∆t = 1/3 seconds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A mass is hung from a spring and set in motion so that it oscillates continually up and down. The velocity v of the weight at time t is ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers