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8 April, 09:55

What will the angle of refraction be for a ray of light passing from air into a sodium chloride crystal if the angle of incidence is 60.0°? The index of refraction of sodium chloride is 1.53.

A. 13°

B. 22°

C. 34°

D. 42°

E. 48°

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Answers (2)
  1. 8 April, 11:25
    0
    Using Snell's Law:

    n1 * sin (theta1) = n2 * sin (theta2)

    where

    n1 is the refractive index of the incident light (n1 = 1 in this case)

    theta1 is the angle of incidence

    n2 is the refractive index of the material that the light is entering (n2 = 1.53 in this case)

    theta2 is the angle of refraction

    n1 * sin (theta1) = n2 * sin (theta2)

    becomes

    1 * sin (60) = 1.53 * sin (theta2)

    or

    1 * 0.866 = 1.53 * sin (theta2)

    0.866 = 1.53 * sin (theta2)

    sin (theta2) = 0.866 / 1.53 = 0.566

    theta2 = arcsin (0.566) = 34 degrees (the angle of refraction)
  2. 8 April, 11:52
    0
    It should be 34 degrees because i took the test

    Explanation:

    Took the test
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