You carry a 2.20 kg bag of groceries at a height of 0.600 m above the level floor at a constant velocity of 0.900 m/s across a room that is 1.60 m long. Find the total work done on the groceries during the process.

0 J.

Explanation:

Given,

mass of the bag, m = 2.20 Kg

height, h = 0.6 m

velocity, v = 0.9 m/s

length, L = 1.60 m

Total work done = ?

Work done = Force x distance

W = F h cos θ

Angle between Force and displacement is equal to 90°.

W = F h cos 90°

W = 0 J

Hence, work done is equal to 0 J