Ask Question
2 April, 08:15

A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at the same level. What is the initial force that must be applied to the

+3
Answers (1)
  1. 2 April, 12:01
    0
    F₂ = 925.92 N

    Explanation:

    In a hydraulic lift the normal stress applied to one arm must be equally transmitted to the other arm. Therefore,

    σ₁ = σ₂

    F₁/A₁ = F₂/A₂

    F₂ = F₁ A₂/A₁

    where,

    F₂ = Initial force that must be applied to narrow arm = ?

    F₁ = Load on Wider Arm to be raised = 12000 N

    A₁ = Area of wider arm = πr₁² = π (18 cm) ² = 324π cm²

    A₂ = Area of narrow arm = πr₂² = π (5 cm) ² = 25π cm²

    Therefore,

    F₂ = (12000 N) (25π cm²) / (324π cm²)

    F₂ = 925.92 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil and capped at both ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers