An unknown material has a mass

of 5.61 kg, and its temperature

increases by 0.124°C when

1320 J of heat are added. What is

the specific heat of the material?

(Unit = J / (kg*C))

1897.53J/Kg°C

Explanation:

Data obtained from the question include:

M (mass of material) = 5.61 kg

ΔT (change in temperature) = 0.124°C

Q (heat) = 1320 J

C (specific heat capacity of the material) = ?

Using the formula Q = MCΔT, the specific heat capacity of the material can be obtained as follow:

Q = MCΔT

C = Q / MΔT

C = 1320J / (5.61 kg x 0.124°C)

C = 1897.53J/Kg°C

Therefore, the specific heat capacity of the material is 1897.53J/Kg°C

Answer: 1896.55J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1320 joules

Mass of material = 5.61kg

C = ? (let unknown value be Z)

Φ = 0.124°C

Then, Q = MCΦ

1320J = 5.61kg x Z x 0.124°C

1320J = 0.696kg°C x Z

Z = (1320J / 0.696kg°C)

Z = 1896.55 J/kg°C

Thus, the specific heat of the material is 1896.55J/kg°C