The hydrogen atom consists of a proton of mass 1.67x10-27 kg and an orbiting electron of mass 9.11x10-31 kg. In one of its orbits, the electron is 5.3x10-11 m from the proton. What is the mutual attractive gravitational force between the electron and the proton?

The mass of the proton,

m

p

=

9.11

*

10

-

31

k

g

The mass of the electron,

m

e

=

1.67

*

10

-

27

k

g

The distance between them,

r

=

5.3

*

10

-

11

m

The gravitational force between two objects of mass,

m

1

, and

m

2

, separated by a distance,

r

, is given by the following equation:

F

=

G

m

1

m

2

r

2

Here,

G

=

6.67

*

10

-

11

m

3

/

k

g

.

s

2

is the gravitational constant.

On plugging the given values, we have:

F

=

6.67

*

10

-

11

*

1.67

*

10

-

27

*

9.11

*

10

-

31

(

5.3

*

10

-

11

)

2

=

3.61

*

10

-

47

N