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8 May, 11:29

An arrow is shot vertically upward from a platform 33ft high at a rate of 214ft/sec. when will the arrow hit the ground? use the formula: h=-16t2+v0t+h0. (round your answer to the nearest tenth.)

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  1. 8 May, 15:24
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    Time = 11.1 seconds

    Explanation:

    h = - 16t^2 + v (0) t + h (0)

    but we are given;

    v (0) = 174 ft/sec

    h (0) = 33 ft

    Find h = 0:

    Therefore;

    0 = - 16t^2 + 174t + 33

    16t^2 - 174t - 33 = 0

    Use the quadratic equation:

    a = 16

    b = - 174

    c = - 33

    t = (174 + / - sqrt ((-174) ^2 - 4 (16) (-33))) / 2 (16)

    t = (174 + / - sqrt (30276 + 2112)) / 32

    t = (174 + / - sqrt (32388)) / 32

    t = (174 + / - 179.97) / 32

    t = 353.97/32 or - 5.97/32

    t = 11.1 or -.2

    Therefore;

    The arrow will hit the ground at:

    t = 11.1 sec
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