The flywheel of a gasoline engine is required to give up 600 j of kinetic energy while its angular velocity decreases from 790 rev/min to 450 rev/min. what moment of inertia is required?

= 0.2594 Kgm²

Explanation:

Using the formula;

K. E = 1.2*I*ω²

Where; K. E is the kinetic energy, I is the moment of inertia and ω is the angular velocity.

Therefore;

ω1 = 790/60 * 2π

= 82.74 rad/sec

ω2 = 450/60 * 2π

= 47.13 rad/sec

600J = 1/2 * I * (82.74²-47.13²)

600 J = 0.5 * I * 4,624.67

600 J = 2312.34 I

I = 0.2594 Kgm²

Moment of inertia = 0.2594 Kgm²