An initially uncharged 3.53 * 10 - 6 F capacitor and a 7290 Ω resistor are connected in series to a 1.50 V battery that has negligible internal resistance. What is the initial current I 0 in the circuit?

The initial current, Io = 2.06*10^-4A

Explanation:

The I itial current, Io of a circuit is given by:

Io = Vo/R

Where Vo = initial votage

R = resistance in ohms

Given:

Vo = 1.50V

R = 7290ohms

Io = 1.50 / 7290

Io = 2.06 * 10^-4A