Two resistors have resistances R1 = (24 + - 0.5) ohm and R2 = (8 + -0.3) ohm. Calculate the absolute error and the percentage relative error in calculating the combination of two resistances when they are in parallel.

Absolute error=0.006

Percentage Relative error=0.6

Explanation:

The resistors have resistance of 24 ohm and 8 ohm.

The change in resistance is 0.5 and 0.3 ohm respectively.

Relative error for parallel combination of resistors is

= dR/R²

= dR1/R1² + dR2/R2²

= 0.5 / (24) ² + 0.3 / (8) ²

= 0.5 / 24*24 + 0.3 / 64

= 0.5/576+0.3 / 64

= 32 + 172.8 / 36,864

=204.8 / 36,864=0.0055

=0.006

Percentage error = Relative error * 100

= 0.006 * 100 = 0.6