A scooter has a mass of 250. Kg. A constant force is exerted on it for 60.0 S. during the time the force is exerted, the scooter increases its speed from 6.00 m/s to 28.0 m/s. What is the change in momentum? What is the magnitude of the force exerted on the scooter?

Question

Physics

Talan Klein

10 December, 04:32

A scooter has a mass of 250. Kg. A constant force is exerted on it for 60.0 S. during the time the force is exerted, the scooter increases its speed from 6.00 m/s to 28.0 m/s. What is the change in momentum? What is the magnitude of the force exerted on the scooter?

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Lexie Orozco · Answer 1

change in momentum = m (v - u); m is mass, V is final velocity and u is initial velocity.

= 250 (28 - 6)

= 5500. N. s

for calculating magnitude of force we shall apply the concept of impulse

Impulse = F X t = m (v-u); F is force applied for time t.

F x 60 = 5500

F = 91.67 N.

force exerted = 91.67 N.