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26 June, 14:15

A woman is pushing a 38.7kg lawnmower initially at rest with a 68.7N forward force against friction. The lawnmower speeds up to 1.44m/s in 3.81s. How much force does friction evert on the mower

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  1. 26 June, 14:49
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    expected acceleration = 68.7/38.7=1.77 m/s^2

    witnessed acceleration = 1.44/3.81 = 0.37 m/s^2

    difference = 1.4m/s^2

    so friction = 38.7 * 1.4 = 54.18 N
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