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29 January, 05:29

An elevator is initially moving upward at a speed of 12.60 m/s. The elevator experiences a constant downward acceleration of magnitude 3.60 m/s2 for 2.97 s.

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  1. 29 January, 07:45
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    I'm assuming you're asking for the elevator's final velocity.

    Consider the following equation:

    Vf = Vi + aΔt

    Vf is the final velocity.

    Vi is the initial velocity.

    a is the acceleration.

    Δt is the amount of elapsed time.

    Given values:

    Vi = 12.60m/s

    a = - 3.60m/s²

    Δt = 2.97s

    Substitute the terms in the equation with the given values and solve for Vf:

    Vf = 12.60 - 3.60*2.97

    Vf = 1.91m/s
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