Ask Question
4 January, 20:25

A 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. The beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. How long is the beam?

+5
Answers (1)
  1. 5 January, 00:12
    0
    let the length of the beam be "L"

    from the diagram

    AD = length of beam = L

    AC = CD = AD/2 = L/2

    BC = AC - AB = (L/2) - 1.10

    BD = AD - AB = L - 1.10

    m = mass of beam = 20 kg

    m₁ = mass of child on left end = 30 kg

    m₂ = mass of child on right end = 40 kg

    using equilibrium of torque about B

    (m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)

    30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)

    L = 1.98 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. The beam ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers