Ask Question
8 October, 04:04

The student finds that a standing wave with one antinode is formed on the string when the frequency of the oscillator is f0. The student then moves the oscillator to shorten the horizontal segment of string to a fourth of its original length. At what frequency will a standing wave with one antinode now be formed on the string?

+5
Answers (1)
  1. 8 October, 05:04
    0
    A standing wave with one antinode in a string means fundamental mode of vibration being formed. In this case

    wave length = 2 x length of string

    λ = 2L

    frequency = velocity of sound / wavelength

    = V / 2L

    f₀ = V / 2L

    new length

    l = L / 4

    When one antinode now be formed on the string

    again fundamental mode of vibration

    wave length = 2 x length of string

    λ₁ = 2l, λ₁ is new wavelength, l is new length.

    frequency = velocity of sound / wavelength

    F₀ = V / 2l, F₀ is new frequency,

    F₀ = 4V / 2L

    = 4 (V / 2L)

    = 4 x f₀

    required frequency = 4f₀

    four times the previous frequency will be required.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The student finds that a standing wave with one antinode is formed on the string when the frequency of the oscillator is f0. The student ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers