a mass of 0.400 is raised by a vertical distance of 0.450m in the earths growth gravitational field. what is the change in its gravitatioanal potential energy? show your work

Complete question: A mass of 0.400 kg is raised by a vertical distance of 0.450 m in the earth's gravitational field. What is the change in its gravitational potential energy?

Answer:

1.764 J

Explanation:

Gravitational Potential Energy: This ca be defined as the energy possessed by a body due to its position in the gravitational field. The S. I unit is J.

The expression for change in Gravitational potential energy is

ΔEp = mgΔh ... Equation 1

Assuming the ground level = 0 m

Where ΔEp = change in Gravitational potential energy, m = mass, g = acceleration due to gravity, h = change in height.

Given: m = 0.40 kg, Δh = 0.450 m, g = 9.8 m/s²

Substitute into equation 1

ΔEp = 0.4 (0.45) (9.8)

ΔEp = 1.764 J

Hence the change in gravitational potential energy = 1.764 J

w = 1.766 Joule

Explanation:

Work = Force * Distance

In this case the Work done is stored in body as Gravitational potential energy, so, W = P. E. = mgh

Here m = 0.400 kg (unit not given in the question if in other unit may be converted to Kg), g = 9.81 m/s² and h = 0.450 m

w = 0.400 kg * 9.81 m/s² * 0.450 m

w = 1.7658 kg m²/s² = 1.766 Joule or (Nm)