A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 17 m/s at an angle θ = 27 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

With what speed, vf in meters per second, does the stone strike the ground?

Question

Physics

Amara

3 August, 18:07

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 17 m/s at an angle θ = 27 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

With what speed, vf in meters per second, does the stone strike the ground?

+3

Answers (1)

Know the Answer?

Daniella Weaver · Answer 1

The stone strikes the ground in 14.71m/s

Explanation:

The initial vertical velocity of the stone is given by:

Vyo = VSin theta

Given: V = 17m/s, theta = 27°

Vyo = 17 Sin 27

Vyo = 7.72m/s

Final vertical velocity, Vf can be determined by using kinematic equation

Vf^2 - U^2 = 2as

Vf^2 - (7.72) ^2 = 2 (9.8 * (-8))

Vf^2 = 59.60 + 156.8

Vf^2 = 216.4

Vf = sqrt (216.4)

Vf = 14.71m/s