When Reggie stepped up to the plate and hit a. 15 kg fast ball traveling at 36m/s the impact caused the ball to leave his bat with a velocity of 45m/s in the oppsite direction. If the impact lasted 0.0020s, what force did Reggie exert on the ball

Assuming the initial direction of motion before impact as negative and final direction of motion as positive.

m = mass of the ball being hit = 0.15 kg

v₀ = initial velocity of the ball before the impact = - 36 m/s

v = final velocity of the ball after impact = 45 m/s

t = time of impact = 0.0020 s

F = force Reggie exerted on the ball

Using Impulse-change in momentum equation

F t = m (v - v₀)

F (0.0020) = (0.15) (45 - ( - 36))

F = 6075 N