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31 May, 15:58

A car travels at uniform acceleration over a distance of 440.0 m. Its initial velocity is 11.0 m/s. What is its final velocity after 20.0 s?

207.0 m/s

11.0 m/s

22.0 m/s

33.0 m/s

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  1. 31 May, 18:48
    0
    x=v0t+1/2at^2

    x=440 m

    v0=11 m/s

    t=20 s

    Solve for a

    440=11 (20) + 1/2a20^2

    440=220+1/2a*400

    220=1/2a*400

    440=400a

    1.1=a

    Now we can use V=V0+at

    V=11+1.1*20

    V=33 m/s
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