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22 November, 03:22

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

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Answers (2)
  1. 22 November, 03:49
    0
    8m/s

    Explanation:

    a=d/t

    a=32/4

    a=8 m/s
  2. 22 November, 05:44
    0
    -8m/s^2

    Explanation:

    initial velocity (u) = 32m/s

    Final velocity (v) = 0

    Time (t) = 4seconds

    Acceleration (a) = ?

    v=u+axt

    0=32+ax4

    -32=4a

    a=-32/4

    a=-8m/s^2
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