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27 January, 05:37

a jack in the box is built around with a spring constant of 70N/m. How much hard does the spring push when you compress it from 40 cm long down to 15 cm long?

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  1. 27 January, 05:55
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    Answer: 17.5N

    Explanation:

    Given that,

    spring constant (k) = 70N/m

    Original length (lo) = 40 cm

    New length (ln) = 15 cm

    extension of spring (e) = new length - original length

    i. e e = ln - lo

    e = 15 cm - 40 cm

    e = - 25cm (the negative sign is negligible, just the same magnitude matters)

    So, convert 25cm to metres

    If 100cm = 1m

    25cm = 25/100 = 0.25m

    (Note that how hard the spring push refers to the Force, hence, find force.)

    Now, apply the Hooke law (F = ke)

    Force = spring constant x extension

    F = 70N/m x 0.25m

    F = 17.5N

    Thus, the spring push with a force of 17.5N when compressed.
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