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13 August, 23:28

dado los vectores a=3.5 b=4 c=6.5, si se sabe que a+b+c=0 (resultante) cual es el angulo formado por A y B?

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  1. 14 August, 01:58
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    cos (A) = (b2 + c2 - a2) / 2bc = (16+6.5^2-3.5^2) / (2*4*6.5) = 0.88461538 so A = cos-1 (0.88461538) = 27.79 Deg cos (B) = (c2 + a2 - b2) / 2ca = (3.5^2+6.5^2-16) / (2*3.5*6.5) = 0.84615385 so B = cos-1 (0.84615385) = 32.2 Deg
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