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27 September, 06:27

Kinematic: An object drop 20m from a cliff. If it started at rest and is going 20m/s just before it hits the ground, what is it's acceleration?

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Answers (2)
  1. 27 September, 07:46
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    h=average v * time average v = (0 + 20) / 2 = 10 so: h = 20 = 10 * t - -> t = 2 sec final v = v0 + at v0=0 - -> 20 = 0 + a*2 - > a = 10 m/s2
  2. 27 September, 08:15
    0
    10 m/s²

    Explanation:

    a = ?

    h = 20m,

    u (initial velocity) = 0 m/s (since it starts at rest,

    v = 20m/s

    Using equation of motion,

    V² = U² + 2as

    V² - U² = 2as

    a = (v² - u²) / 2s

    a = (20² - 0) / 2 * 20

    a = 400 / 40

    a = 10 m/s²
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