While taking a bath, a person touches the metal case of a radio. The path through the person to the drainpipe and ground has a resistance of 4350 Ω. What is the smallest voltage (in V) on the case of the radio that could cause ventricular fibrillation?

Given:

Resistance, R = 4350 Ω

Smallest current to cause a ventricular fibrillation, I = 0.1 A

Using ohm's law,

Voltage, V = I * R

= 0.1 * 4350

= 435 V.

Smallest voltage = 435 V.

435V

Explanation:

To calculate the smallest voltage that could cause ventricular fibrillation

(Know that the smallest current (I) in that could bring about ventricular fibrillation is 100mA = 0.1 A (ampere)

We're given resistance to be 4350 Ω

Therefore we use Ohms law equation

V = IR

V = 0.1 * 4350

V = 435V