Ask Question
15 April, 20:16

A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, what is the force in the narrow part of the pipe?

+4
Answers (1)
  1. 15 April, 23:36
    0
    Use direct proportionality: If 1.25 m = 72 N, then 0.55 m = y

    0.55 m * 72 = 39.6.

    39.6:1,25 gives you your answer which is 31.68 N.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, what is the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers