Question 5 - A gas occupies 60 liters at a pressure of 40.0 mm Hg. What is the volume when the pressure is

increased to 60.0 mm Hg?

60L

.666L

40L

100L

40L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 60L

P1 (initial pressure) = 40mmHg

V2 (final volume) = ?

P2 (final pressure) = 60mmHg

Using P1V1 = P2V2, the final volume can be obtain as illustrated below:

P1V1 = P2V2

40 x 60 = 60 x V2

Divide both side by 60

V2 = (40 x 60) / 60

V2 = 40L

Therefore, the final volume is 40L