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29 January, 08:29

A meter stick is balanced at the 50 cm mark. You tie 70 N weight at the 30 cm mark. What weight at the 90 cm mark would create a rotational equilibrium?

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  1. 29 January, 11:40
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    70x (50-30) = W x (90-50)

    1400 = W x 40

    W = 35N
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