A rock, thrown straight up, takes 4.2 seconds to reach its max height (g=9.8m/s) what was the initial velocity? what was its maximum height?

Question

Physics

Eden Johnston

28 April, 16:31

A rock, thrown straight up, takes 4.2 seconds to reach its max height (g=9.8m/s) what was the initial velocity? what was its maximum height?

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Answers (1)

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Dominic Duran · Answer 1

Known dа ta:

time=4,2s

Earth's acceleration:9.8m/s²

Formulas needed:

t=v:g

S=vt + (gt²) : 2

Solution:

t=v:g

4,2=v:9,8

v=9,8*4,2

v=41,16m/s

S=vt + (gt²) : 2

S=41,16*4,2-9.8 * (4,2) ²:2

S=86.436m