A 0.0414 kg ingot of metal is heated to 243◦C

and then is dropped into a beaker containing 0.411 kg of water initially at 18◦C.

If the final equilibrium state of the mixed system is 20.4◦C, find the specific heat of the metal. The specific heat of water is 4186 J/kg ·◦ C.

Answer in units of J/kg ·◦ C.

Question

Physics

Moises Fischer

2 July, 03:34

A 0.0414 kg ingot of metal is heated to 243◦C

and then is dropped into a beaker containing 0.411 kg of water initially at 18◦C.

If the final equilibrium state of the mixed system is 20.4◦C, find the specific heat of the metal. The specific heat of water is 4186 J/kg ·◦ C.

Answer in units of J/kg ·◦ C.

+4

Answers (1)

Know the Answer?

Cody · Answer 1

448 J/kg/°C

Explanation:

m₁ C₁ (T₁ - T) + m₂ C₂ (T₂ - T) = 0

(0.0414 kg) C (243°C - 20.4°C) + (0.411 kg) (4186 J/kg/°C) (18°C - 20.4°C) = 0

(9.22 kg°C) C - 4129 J = 0

C = 448 J/kg/°C