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28 March, 11:42

a hot metal bolt of mass 0.05 kg and specific heat capacity 889 joules per kg degree celsius is dropped into a calorimeter containing 0.15 kg water at 21 degrees celsius. the bolt and water resch a final temperature of 25 degrees celsius. what is the initial temperature of the bolt? the specific heat capacity of water is 4186 joules per kilogram degrees celsius.

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  1. 28 March, 14:50
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    Answer;

    80.87 °C

    Explanation;

    Change in Temp of metal = (C of water * mass of water * Change in temp of water) / (C of metal*mass of metal)

    That is;

    Change of temp. of metal

    = [ (4186 J/kg*°C) * (0.15kg) * (25°C-21°C) / [ (899 j/kg*C) * (0.050kg)

    = 55.87 °C

    The change in temp of the metal is - 55.87 °C as the metal cools down

    Therefore;

    Change in temperature = Final Temperature-Initial Temperature Initial Temperature = Final Temp.-Change in Temp

    =25 °C - (-55.87 °C)

    = 80.87 °C
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