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26 February, 13:26

A piston-cylinder device contains 3 kg of saturated water vapor at 200 kPa. Now heat is transferred to the system at constant pressure until the temperature reaches 200oC. Calculate the work done by the steam during this process.

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  1. 26 February, 13:57
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    work done = 117 kJ

    Explanation:

    given data

    mass m = 3 kg

    constant pressure P = 200 kPa

    temperature T = 200°C

    solution

    we know that work done by steam is express as

    work done = pressure * ΔVolume ... 1

    and here ΔVolume = final volume - initial volume

    we use here steam table and get at pressure 200 kPa

    final specific volume = 1.08052 m³/kg

    and

    initial specific volume = 0.885735 m³/kg

    so here

    ΔV = 3 * (1.08052 - 0.885735)

    ΔV = 0.584 m³

    so put value in equation 1 we get

    work done by steam = 200 * 0.584

    work done = 117 kJ
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