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28 March, 09:50

An initially uncharged 3.67 μF capacitor and a 8.01 k Ω resistor are connected in series to a 1.50 V battery that has negligible internal resistance. What is the initial current in the circuit, expressed in milliamperes?

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  1. 28 March, 13:25
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    The initial current in the circuit is 0.1873 mA

    Explanation:

    Given;

    capacitance is given as 3.67 x 10⁻⁶ F

    resistance is given as 8010 Ω

    voltage across the circuit is 1.5 V

    Since the capacitor is initially uncharged, the capacitive reactance is zero.

    From ohms law;

    Voltage across the circuit is directly proportional to the opposition to the flow of current.

    V = IR

    I = V/R

    I = 1.5/8010

    I = 0.0001873 A = 0.1873 mA

    Therefore, the initial current in the circuit is 0.1873 mA
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