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5 January, 19:59

A 2.5 kg stone is released from rest and falls toward Earth. After 4.0 s, magnitude of its momentum in kg. m/s is:

A-78

B-98

C-122.5

D-24.7

+4
Answers (2)
  1. 5 January, 21:37
    0
    Answer:B

    Explanation:

    Initial velocity (u) = 0

    Time (t) = 4seconds

    Mass (m) = 2.5kg

    acceleration due to gravity (g) = 9.8m/s^2

    Final velocity (v) = u+gxt

    Final velocity (v) = 0+9.8x4

    Final velocity (v) = 39.2m/s

    Momentum=mass x velocity

    Momentum=2.5 x 39.2

    Momentum=98kgm/s
  2. 5 January, 23:35
    0
    B

    Explanation:

    momentum = mass * velocity

    velocity = initial speed + acceleration * time where initial speed = 0, acceleration = 9.81, time = 4
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