How much water must the jogger's body evaporate every minute due to his activity? the heat of vaporization of water at body temperature is 2.42*106 j/kg?

The mass of water, jogger body evaporates every minute is 0.117 gm/min.

The average jogger body reseal heat at a rate of 284 J/min.

Therefore the mass of water vapour evaporate from the jogger body is calculated as

Q=ml

284=m*2.42*10^6 J/kg

m=0.117 gm/min