an object moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm if its x coordinate 2.00 s later is - 5.00cm what is its acceleration

Given:

at time t=0, X0=X (0) = 3.00 cm, v (0) = 12 cm/s

at time t=2, x (2) = -5

Use kinematics equation:

X (t) = X (0) + v (0) * t+at^2/2

Substitute = >

X (t) = 3+12t+at^2/2

At t=2, X (2) = -5 = >

-5=3+12 (2) + a (2^2) / 2 = >

acceleration = a = (-5-3-24) / 2 = - 16 cm/s^2