Particle with a mass of 1.7 * 10-20 kg is oscillating with simple harmonic motion with a period of 3.4 * 10-5 s and a maximum speed of 2.6 * 103 m/s. calculate (a) the angular frequency and (b) the maximum displacement of the particle.

(a) angular frequency = ω=184706 rad/s

Explanation:

angular frequency = ω = 2π/T

T = time period = 3.4 x 10⁻⁵ s

ω = 2π / (3.4 x 10⁻⁵)

ω=184706 rad/s

(b) maximum displacement of the particle = a=0.0141 m

Explanation:

maximum velocity is given by Vmax = aω

a = amplitude of maximum displacement

ω = angular frequency

2.6 x 10³ = a (184706)

a=0.0141 m