An unknown solid weighs 31.6 n. when submerged in water, its apparent weight is 19.8 n. what is the specific gravity of the unknown sample?

specific gravity of the unknown sample = 2.68

Explanation:

True weight of solid=31.6 N

Apparent weight=19.8 N

loss in weight = 31.6-19.8=11.8 N

Loss in weight = weight of the liquid displaced

so weight of water displaced = 11.8 N

now specific gravity = weight of object / weight of liquid displaced

specific gravity = 31.6/11.8

specific gravity = 2.68