A force of 83 newtons is applied to a wire with a diameter of 0.5 mm. what is the tensile stress (in n/m2) in the wire? do not include units with the answer.

Tensile stress=4.23 x 10⁸ N/m²

Explanation:

Tensile stress = F/a

F = force = 83 N

a = area = πr² where r is the radius

d = diameter = 0.5 mm

r = d/2=0.5/2=0.25=0.00025 m

a=π (0.00025) ² = 1.963 x 10⁻⁷ m²

Tensile stress = 83 / (1.963 x 10⁻⁷)

Tensile stress=4.23 x 10⁸ N/m²