A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement? (Use trigonometry to solve.) x = y =.

x = 193 m

y = 135 m

Total displacement along the length of mountain is given as

L = 235 m

angle of mountain with horizontal = 35 degree

now we will have horizontal displacement as

x = L cos35

x = 235 cos35 = 192.5 m

similarly for vertical displacement we can say

y = L sin35

y = 235 sin35 = 134.8 m