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14 November, 20:19

A series RCL circuit includes a resistance of 280, an inductive reactance of 508, and a capacitive reactance of 315. The current in the circuit is 0.312 A. What is the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

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  1. 14 November, 21:23
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    The voltage of the generator is 88.53volts

    Explanation:

    The voltage across the RLC AC circuit will be the voltage across the generator. It is expressed as

    V = IZ and

    Z² = R² + (Xl-Xc) ²

    Z = √R² + (Xl-Xc) ² where;

    Z is the impedance that oppose the flow of current in the resistor, capacitor and inductor in the circuit

    I is the total current = 0.312A

    R is the resistance in the circuit = 280ohms

    Xl is the inductive reactance = 508ohms

    Xc is the capacitive reactance = 315ohms

    Substituting to this parameters to get the impedance Z we have;

    Z = √280² + (508-315) ²

    Z = √208² + (193) ²

    Z = √80,513

    Z = 283.75ohms

    The voltage V of the generator = current * impedance

    V = 0.312*283.75

    V = 88.53Volts

    The voltage if the generator is 88.53volts
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