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7 April, 13:30

Earthquakes produce transverse waves. If a secondary wave of an earthquake is measured from crest to crest to be 23000 m and it travels at 4500 m/s, calculate the wave's frequency.

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Answers (2)
  1. 7 April, 15:52
    0
    0.196 Hz

    Explanation:

    Parameters given:

    Wavelength = 23000 m

    Velocity = 4500 m/s

    (the wavelength is the measurement from one crest to the next crest or from one trough to the next trough)

    Velocity of wave is given as:

    Velocity = Wavelength * frequency

    Frequency can then be given as:

    Frequency = velocity/wavelength

    Frequency = 4500/23000 = 0.196 Hz
  2. 7 April, 17:14
    0
    0.196 Hz

    Explanation:

    Frequency: This can be defined as the number of revolution covered by a wave in one seconds. The S. I unit of frequency is Hertz (Hz)

    Using

    v = λf ... Equation 1

    Where v = velocity of wave, λ = wave length, f = frequency.

    Note: Distance from crest to crest of a wave is it's wave length.

    Make f the subject of the equation

    f = v/λ ... Equation 2

    Given: v = 4500 m/s, λ = 23000 m

    Substitute into equation 2

    f = 4500/23000

    f = 0.196 Hz

    Hence the wave frequency = 0.196 Hz
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