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29 April, 04:36

A negative charge of - 2.0 C and a positive charge of 3.0 C are separated by 80 m. What is the force between the two charges?

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  1. 29 April, 06:11
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    Answer: - 8.4 x 10^6N

    Explanation:

    Given that,

    negative charge (q1) = - 2.0C

    positive charge (q2) = 3.0C

    Distance between charges (r) = 80 m

    force between the two charges (F) = ?

    Apply the formula for

    F = (kq1q2) / r^2

    Recall that k is Coulomb's constant with a value of 9 * 10^9 Nm2C-2

    Then,

    F = (9 * 10^9 Nm2C-2 x - 2.0C x 3.0C) / (80m) ^2

    F = (-5.4 x 10^10) / (6400m) ^2

    F = - 8437500N

    Place result in standard form

    F = - 8.4 x 10^6N

    Thus, the force between the two charges is - 8.4 x 10^6 newton
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