If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 25.0 km? Take the mass of the sun to be ms = 1.991030 kg, the gravitational constant to be G = 6.6710-11 N⋅m2/kg2, and the free-fall acceleration at the earth's surface to be g = 9.8 m/s2.

Question

Physics

Jamal Lopez

30 January, 21:31

If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 25.0 km? Take the mass of the sun to be ms = 1.991030 kg, the gravitational constant to be G = 6.6710-11 N⋅m2/kg2, and the free-fall acceleration at the earth's surface to be g = 9.8 m/s2.

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Jamal Stokes · Answer 1

Given that,

Mass of star M (star) = 1.99*10^30kg

Gravitational constant G

G = 6.67*10^-11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W = mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g (star) = GM (star) / R²

g (star) = 6.67*10^-11 * 1.99*10^30 / 12500²

g (star) = 8.49 * 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 * 8.49 * 10¹¹

W = 5.98 * 10¹³ N

The weight of the person on neutron star is 5.98 * 10¹³ N