Ask Question
17 April, 10:33

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater than atmospheric pressure? The density of glycerine is 1.26 * 10 3 kg/m 3.

+1
Answers (1)
  1. 17 April, 14:17
    0
    Answer: 0.176 m

    Explanation:

    Given

    Pressure of glycerine, p = 2170 Pa

    Density of glycerine, ρ = 1.26*10^3 kg/m³

    Depth, h = ?

    To solve, we use the formula of pressure

    P = ρgh

    Where

    ρ = density of glycerine

    P = pressure of glycerine

    g = acceleration due to gravity

    h = depth of glycerine

    2170 = 1.26*10^3 * 9.8 * h

    2170 = 12348 * h

    h = 2170 / 12348

    h = 0.176 m

    Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater than ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers