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20 February, 16:37

Given the following lens combination:

Lens ... diameter ... fl#

eyepiece ... 2cm ... 5

objective ... 40cm ... 15

what is the magnification?

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Answers (2)
  1. A
    20 February, 16:58
    0
    Given:

    Lens ... diameter ... fl#

    eyepiece ... 2cm ... 5

    objective ... 40cm ... 15

    focal length of eyepiece = 2*5 = 10cm

    focal length of objective = 40*15 = 600cm

    magnification = FL obj / FL eyp = 600/10 = 60x
  2. R
    20 February, 17:19
    0
    magnification = (40*15) / (2*5) = 60X
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