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10 April, 10:06

A particle is located on the x axis at x = 2.0 m from the origin. A force of 25 N, directed 30° above the x axis in the x-y plane, acts on the particle. What is the torque about the origin on the particle?

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  1. 10 April, 11:40
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    25 Nm

    Explanation:

    Parameters given

    Distance of the particle from the origin, r = 2.0 m

    Force acting on particle, F = 25 N

    Angle of force, θ = 30°

    The torque acting on a particle is given as:

    τ = r * F * sinθ

    Where r = radius of axis of rotation. This is the same as the position of the particle on the x axis.

    Therefore, the torque will be:

    τ = 2 * 25 * sin30

    τ = 25 Nm

    The torque acting on the particle is 25 Nm.
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