Capacitors A and B are identical. Capacitor A is charged so it stores 4 J of energy and capacitor B is uncharged. The capacitors are then connected in parallel. The total stored energy in the capacitors is now:

A. 16 J

B. 8 J

C. 4 J

D. 2 J

E. 1 J

B. 8 J

Explanation:

From the question,

The voltage in each of the identical capacitor is given as

W = 1/2CV² ... Equation 1

Where Q = charge, V = potential difference, C = Capacitance of the capacitor.

make V the subject of the equation

V = √ (2W/C) ... Equation 2

Given: W = 4 J,

Substitute into equation 2 and find the value of V in terms of C

V = √ (8/C)

Since both capacitor were connected in parallel,

The total potential difference = potential difference of on of the capacitor = √ (8/C)

Total capacitance = 2C.

using equation 1,

W = 1/2 (√ (8/C)) ²*2C

W = 8 J.

Hence the right option is B. 8 J