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28 February, 23:37

A car travelled 60 km west in 1.33 h along a straight line, then returned back east for 40 km in 0.67 h. Its average velocity is:

a) 10 km/h, east.

b) 10 km/h, west.

c) 50 km/h, east.

d) 50 km/h, west.

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Answers (1)
  1. 28 February, 23:47
    0
    Option A

    Explanation:

    Velocity is expressed as distance covered per unit time, with respect to direction. Therefore, v=d/t

    Given distance west as 60 km and time as 1.33 then velocity will be

    V=60/1.33=45.112781954887 km/h

    Rounded off as 45.11 km/h West

    Velocity in East will also be given by substituting 40 km for d and 0.67 h for h hence

    V=40/0.67=59.701492537313 km/h rounded off as 59.70 km/h East

    Taking East as positive then West as negative, the sum of two velocities will be (59.70+-45.11) / 2=7.295 km/h East

    Approximately 10 km/h East since it is positive
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