What is the electric force acting between two charges of 0.0042 C and - 0.0050 C that are 0.0030 m apart?

A. - 2.1 1010 N

B. 2.1 1010 N

C. 6.3 107 N

D. - 6.3 107 N

A.-2.1 * 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force

k is the constant

Q1, Q2 are the two charges and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) * (0.0042) * (-0.0050) / (0.0030) ²

= - 2.1 x 10^10 N

Therefore; electrical force acting between the two charges is - 2.1 x 10^10 N.