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2 November, 14:43

2. The skid marks made by an automobile indicated that its breaks were first applied for a distance of 60 meters (m) before it came to a complete stop. The car in question is known to have a constant deceleration of 20 m/s2 under these conditions. How fast (in km/h) was the car traveling when the brakes were first applied? [Be sure to sketch your coordinate system to clarify the meaning of the functions involved.] Be sure to include units in your answer.

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  1. 2 November, 15:39
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    We shall take motion along x - axis (positive)

    We shall apply the equation of law of motion as follows

    v² = u² - 2aS

    v is final velocity, u is initial velocity, S is displacement and a is deceleration.

    0 = u² - 2 x 20 x 60

    u² = 2 x 20 x 60

    u² = 2400

    u = 49 m / s approx.

    = 49 x 60 x 60 / 1000 km / h

    = 176.4 km / h.
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